Fill in the missing pieces in the conversion of the decimal integer `(53)_{10}` into its binary (base-2) representation.

53 = *(26) + 1
26 = *(13) + 0
13 = *(6) + 1
6 = *(3) + 0
3 = *(1) + 1
1 = *(0) + 1

The binary representation of `(53)_{10}` is `(``)_{2}`